Blinka Retailers accepted $50,000 of Citibank Visa credit card charges for merchandise sold on July 1. Citibank charges 4% for its credit card use. The entry to record this transaction by Blinka Retailers will include a credit to Sales Revenue of $50,000

The first step is to draw a free-body diagram for Block A and Block B. For Block A, there are two forces acting on it: its weight (which we can find using its maximum weight) and the tension force from the string attached to it. We can also break up the tension force into its x and y components. The x component is Tcos(41°) and the y component is Tsin(41°). For Block B, there are also two forces acting on it: its weight and the tension force from the string attached to it. We can also break up the tension force into its horizontal and vertical components. The horizontal component is Tcos(41°), which is also the force of friction since the block is at the brink of sliding. The vertical component is Tsin(41°). Using Newton's second law, we can write down equations for the net force in the x and y directions for each block: For Block A: Tcos(41°) = max(A) (since Block A is not moving horizontally) Tsin(41°) - weight(A) = 0 (since Block A is not moving vertically) For Block B: Tcos(41°) = friction(B) weight(B) - Tsin(41°) = 0 We can now substitute in values for the weight and coefficient of static friction: friction(B) = 0.25 * weight(B) Solving for tension in terms of weight(B): T = weight(B) / cos(41°) Substituting T into the equations for Block A: (weight(B) / cos(41°)) * cos(41°) = max(A) (weight(B) / cos(41°)) * sin(41°) - weight(A) = 0 Solving for weight(A): weight(A) = (weight(B) / cos(41°)) * sin(41°) Substituting in values: weight(B) = 712 N weight(A) = (712 N / cos(41°)) * sin(41°) = 574 N Therefore, the maximum weight of Block A is 574 N.