Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with ammonia NH3. What mass of ammonium phosphate is produced by the reaction of 9.21g of ammonia? Be sure your answer has the corr

The balanced chemical equation for the reaction is: H3PO4 + NH3 ? NH43PO4 To determine the mass of ammonium phosphate produced, we need to first calculate the number of moles of ammonia used in the reaction. We can use the molar mass of ammonia to convert the given mass to moles: 9.21 g NH3 ? (1 mol NH3/17.03 g NH3) = 0.541 mol NH3 Next, we can use the stoichiometry of the balanced equation to determine the number of moles of ammonium phosphate produced. According to the equation, 1 mole of NH3 produces 1 mole of NH4H2PO4. Therefore: 0.541 mol NH3 ? (1 mol NH4H2PO4/1 mol NH3) = 0.541 mol NH4H2PO4 Finally, we can use the molar mass of ammonium phosphate to convert the number of moles to grams: 0.541 mol NH4H2PO4 ? (149.08 g NH4H2PO4/ 1 mol NH4H2PO4) = 80.5 g NH4H2PO4 Therefore, the mass of ammonium phosphate produced is 80.5 g. We have three significant figures in our given mass of ammonia, so we need to round our answer to three significant figures as well. Thus, the final answer is: 80.5 g NH4H2PO4 (to three significant figures)