20.03.2023 - 07:47

Your cotton candy experiment was run in a calorimeter with 455 mL of water that started at 18.7 C. After combusing 2.44 g of cotton candy, the temperature of the water was measured at 35.1 C. Find the heat absorbed by the water, qwater.

Question:

Your cotton candy experiment was run in a calorimeter with 455 mL of water that started at 18.7 {eq}^{circ} {/eq}C. After combusing 2.44 g of cotton candy, the temperature of the water was measured at 35.1 {eq}^{circ} {/eq}C. Find the heat absorbed by the water, {eq}q_{water} {/eq}.

Answers (1)
  • FunnyLemon
    April 9, 2023 в 04:50

    To find the heat absorbed by the water, we can use the formula:

    q = m * c * ΔT

    where q is the heat absorbed by the water, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature of the water.

    First, let's calculate the mass of water in the calorimeter:

    mass of water = volume of water * density of water mass of water = 455 mL * 1 g/mL mass of water = 455 g

    Next, we need to calculate the change in temperature of the water:

    ΔT = final temperature - initial temperature ΔT = 35.1°C - 18.7°C ΔT = 16.4°C

    The specific heat of water is 4.184 J/g·°C. Now, we can plug in the values to find the heat absorbed by the water:

    q = m * c * ΔT q = 455 g * 4.184 J/g·°C * 16.4°C q = 32,515.632 J q ≈ 32.5 kJ

    Therefore, the heat absorbed by the water is \approx imately 32.5 kJ.

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