What mass (in grams) of cobalt(II) nitrate hexahydrate is needed to make 100.0 mL of 0.10 M cobalt(II) nitrate solution?
Question:
What mass (in grams) of cobalt(II) nitrate hexahydrate is needed to make 100.0 mL of 0.10 M cobalt(II) nitrate solution?
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Answers (1)
CamrynApril 2, 2023 в 07:49
The first step to solving this problem is to use the equation:
Molarity = moles of solute / liters of solution
We know the molarity of the solution (0.10 M) and the volume of the solution (100.0 mL, or 0.100 L). We need to find the moles of cobalt(II) nitrate needed to make this solution.
Moles of solute = Molarity x liters of solution
Moles of solute = 0.10 M x 0.100 L
Moles of solute = 0.010 moles of cobalt(II) nitrate
Now we can use the molar mass of cobalt(II) nitrate hexahydrate (237.93 g/mol) to find the mass needed to make 0.010 moles of cobalt(II) nitrate:
Mass = moles x molar mass
Mass = 0.010 moles x 237.93 g/mol
Mass = 2.38 grams of cobalt(II) nitrate hexahydrate
Therefore, to make 100.0 mL of 0.10 M cobalt(II) nitrate solution, we need 2.38 grams of cobalt(II) nitrate hexahydrate.
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