What is the citric acid concentration in a soda if it requires 28.9 mL of 0.01 M NaOH to titrate 25.0 mL of soda?

The citric acid concentration in the soda is 0.01445 M. Explanation: First, we need to write out the balanced chemical equation for the reaction between citric acid and NaOH: H3C6H5O7 + 3 NaOH ? Na3C6H5O7 + 3 H2O We can see from this equation that for every one mole of citric acid (H3C6H5O7), three moles of NaOH are needed for a complete reaction. Since we know the volume (in mL) and concentration (in M) of the NaOH solution used to titrate the soda, we can use the equation: moles of NaOH = volume of NaOH x concentration of NaOH to calculate the number of moles of NaOH used in the titration. moles of NaOH = 28.9 mL x 0.01 M = 0.00289 moles of NaOH Since the reaction between citric acid and NaOH is a 1:3 stoichiometric ratio, the number of moles of citric acid present in the 25.0 mL of soda can be calculated as: moles of citric acid = 0.00289 moles of NaOH x 1 mol of H3C6H5O7 / 3 mol of NaOH x (25.0 mL / 1000 mL) = 1.2075 x 10^-4 moles of H3C6H5O7 Finally, we can calculate the concentration of citric acid in the soda: concentration of citric acid = moles of citric acid / volume of soda = 1.2075 x 10^-4 moles / 25.0 mL = 0.00482 M However, this is only the concentration of one of the three acids present in soda. Therefore, we need to multiply the calculated concentration of citric acid by three (since there are three moles of citric acid in every mole of soda) to get the final answer: concentration of citric acid in soda = 0.00482 M x 3 = 0.01445 M