The production of ethanol for use as a fuel can be accomplished through fermentation of glucose, a type of sugar: C 6 H 12 O 6 ( s ) 2 C H 3 C H 2 O H ( l ) + 2 C O 2 ( g ) . What mass of ethanol can be produced from the fermentation of 7.7 kg of gluc

The balanced chemical equation for the fermentation of glucose to produce ethanol is: C6H12O6 ? 2CH3CH2OH + 2CO2 From the equation, we can see that 1 mole of glucose produces 2 moles of ethanol. The molar mass of glucose is 180 g/mol, and the molar mass of ethanol is 46 g/mol. To find the mass of ethanol produced from 7.7 kg of glucose, we first need to convert the mass of glucose to moles: 7.7 kg glucose x 1000 g/kg / 180 g/mol = 42.8 mol glucose From the equation, we know that 1 mole of glucose produces 2 moles of ethanol, so: 42.8 mol glucose x 2 mol ethanol/mol glucose = 85.6 mol ethanol Finally, we can convert the moles of ethanol to mass: 85.6 mol ethanol x 46 g/mol = 3937.6 g of ethanol Therefore, the mass of ethanol produced from the fermentation of 7.7 kg of glucose is 3937.6 g or 3.94 kg.