The mean gas mileage for a hybrid car is 56 miles per gallon. Suppose that the gasoline mileage is \approx imately normally distributed with a standard deviation of 3.3 miles per gallon. What is the probability that a randomly selected hybrid gets between 5

To find the probability that a randomly selected hybrid gets between 57 and 62 miles per gallon, we need to first calculate the standardized score (z-score) for each value using the formula: z = (x - ?) / ? where x is the value we are interested in, ? is the mean gas mileage (56), and ? is the standard deviation (3.3). For 57 miles per gallon: z = (57 - 56) / 3.3 = 0.3030 For 62 miles per gallon: z = (62 - 56) / 3.3 = 1.8182 Next, we use a standard normal table or a calculator to find the area under the normal curve between these two z-scores. Using a calculator, we can use the normalcdf function with a lower bound of 0.3030 and an upper bound of 1.8182: normalcdf(0.3030, 1.8182) = 0.2671 Therefore, the probability that a randomly selected hybrid gets between 57 and 62 miles per gallon is \approx imately 0.2671 or 26.71%.