Question:
The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
{eq}(a) 2x^ 2 + 3x – 119 = 0\ (b) 3x ^2 + 3x – 119 = 0\ (c) 6x ^2 – 119 = 0 {/eq}
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