The Kingda Ka roller coaster in New Jersey is the world’s tallest ride of its kind. As the passenger cars are launched from rest at the start, they are accelerated uniformly to a speed of 57 m/s (128 mph) in just 3.5 s. (Assume the cars are launched in th

(a) The acceleration experienced by passengers on this ride can be calculated using the equation, a = ?v/?t Where, ?v = change in velocity = 57 m/s (since the cars are launched from rest) ?t = time taken to achieve that velocity = 3.5 s Substituting the values, a = 57/3.5 = 16.3 m/s? To find the acceleration experienced by passengers in g's, we divide this value by the acceleration due to gravity (9.8 m/s?), a = 16.3/9.8 = 1.66 g's Therefore, passengers on the Kingda Ka roller coaster experience an acceleration of 16.3 m/s? or 1.66 g's during the launch phase. (b) The force acting on a passenger with a mass of 80 kg during the launch phase can be calculated using Newton's second law of motion, F = ma Where, m = mass of the passenger = 80 kg a = acceleration of the passenger = 16.3 m/s? Substituting the values, F = 80 x 16.3 = 1304 N Therefore, the force acting on the passenger during the launch phase of the ride is 1304 N. To find the force in pounds, we can convert the value using the conversion factor, 1 N = 0.2248 lbs So, F = 1304 x 0.2248 = 293 lbs Therefore, the force acting on the passenger during the launch phase of the ride is 1304 N or 293 lbs.