19.07.2022 - 02:37

# The bookstore at SunTan U had a sale on school t-shirts. Thursday, they sold 52 of the marked down t-shirts for a total of $482.50. If the women’s shirts were on sale for$9.50 and the men’s shirts were on sale for $9.00, how many of each was sold on Thur Question: The bookstore at SunTan U had a sale on school t-shirts. Thursday, they sold 52 of the marked down t-shirts for a total of$482.50. If the women’s shirts were on sale for $9.50 and the men’s shirts were on sale for$9.00, how many of each was sold on Thursday?

Let's start by assigning variables to the unknowns we need to find: - Let's use "W" for the number of women's shirts sold - Let's use "M" for the number of men's shirts sold We know that a total of 52 shirts were sold on Thursday, so: W + M = 52 We also know the total amount of money earned from these sales was $482.50. If we multiply the number of women's shirts sold by their price ($9.50) and the number of men's shirts sold by their price ($9.00), we get the total amount earned: 9.50W + 9.00M = 482.50 Now we have two equations with two variables, which we can solve using algebraic methods. One way to start is by simplifying the first equation: W + M = 52 W = 52 - M Now we can substitute this expression for W into the second equation: 9.50W + 9.00M = 482.50 9.50(52 - M) + 9.00M = 482.50 Distributing the 9.50: 494 - 9.50M + 9.00M = 482.50 Simplifying: 494 - 0.50M = 482.50 Subtracting 494 from both sides: -0.50M = -11.50 Dividing by -0.50: M = 23 So 23 men's shirts were sold on Thursday. We can use the first equation to find the number of women's shirts: W + M = 52 W + 23 = 52 W = 29 Therefore, 29 women's shirts were sold on Thursday. Do you know the answer? Not sure about the answer? Find the right answer to the question The bookstore at SunTan U had a sale on school t-shirts. Thursday, they sold 52 of the marked down t-shirts for a total of$482.50. If the women’s shirts were on sale for $9.50 and the men’s shirts were on sale for$9.00, how many of each was sold on Thur by subject Equations, and if there is no answer or no one has given the right answer, then use the search and try to find the answer among similar questions.