Suppose there are two rectangular pools: one is 30 feet wide, 60 feet long, and 5 feet deep throughout and the other is 40 feet wide, 50 feet long, and 4 feet deep throughout. Show that each pool can be considered “biggest” by comparing the s

One way to compare the sizes of the two pools is by calculating their volume. The volume of the first pool is calculated as follows: Volume = width x length x depth Volume = 30 x 60 x 5 Volume = 9,000 cubic feet The volume of the second pool is calculated as follows: Volume = width x length x depth Volume = 40 x 50 x 4 Volume = 8,000 cubic feet Therefore, based on volume, the first pool is bigger than the second pool. Another way to compare the sizes of the two pools is by calculating their surface area. The surface area of the first pool is calculated as follows: Surface area = 2(length x width) + 2(width x depth) + 2(depth x length) Surface area = 2(60 x 30) + 2(30 x 5) + 2(60 x 5) Surface area = 4,800 square feet The surface area of the second pool is calculated as follows: Surface area = 2(length x width) + 2(width x depth) + 2(depth x length) Surface area = 2(50 x 40) + 2(40 x 4) + 2(50 x 4) Surface area = 3,200 square feet Therefore, based on surface area, the first pool is bigger than the second pool. By comparing the volume and surface area of the two pools, we can conclude that each pool can be considered 'biggest' in different ways.