Suppose that you have a 700-Ohm, a 790-Ohm, and a 1.20-kOhm resistor. What is the maximum resistance you can obtain by combining these? What is the minimum resistance you can obtain by combining these
Question:
Suppose that you have a 700-{eq}Omega {/eq}, a 790-{eq}Omega {/eq}, and a 1.20-k{eq}Omega {/eq} resistor. What is the maximum resistance you can obtain by combining these? What is the minimum resistance you can obtain by combining these?
Answers (1)
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Answers (1)
InezApril 3, 2023 в 09:00
The maximum resistance can be obtained by connecting all the resistors in series, which means that the total resistance is simply the sum of the individual resistances:
Rmax = 700 + 790 + 1200 = 2690 ?
The minimum resistance can be obtained by connecting all the resistors in parallel, which means that the reciprocal of the total resistance is the sum of the reciprocals of the individual resistances:
1/Rmin = 1/700 + 1/790 + 1/1200
1/Rmin = 0.002857 + 0.002532 + 0.000833
1/Rmin = 0.006222
Rmin = 161 ?
Therefore, the maximum resistance you can obtain by combining these resistors is 2690 ?, and the minimum resistance you can obtain by combining these resistors is 161 ?.
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