Solve the \quadratic equation: 3x^2 + 3x – 36 = 0

The \quadratic formula is used to solve \quadratic equations in the form of {eq}ax^2 + bx + c = 0{/eq}. In this case, a = 3, b = 3, and c = -36. Using the \quadratic formula, {eq}x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\ x = \frac{-3 \pm \sqrt{3^2 - 4(3)(-36)}}{2(3)}\ x = \frac{-3 \pm \sqrt{333}}{6} {/eq} Therefore, the solutions to the \quadratic equation {eq}3x^2 + 3x - 36 = 0{/eq} are {eq}frac{-3 + sqrt{333}}{6}, \frac{-3 - sqrt{333}}{6}{/eq}.