Referring to the given figure where V = 21 V, use source transformation to determine the current and power absorbed by the 8-Ω resistor. The current absorbed by the 8-Ω resistor is _____. The power absorbed by the 8-Ω resistor is _____

The current absorbed by the 8-? resistor is 2.625 A. The power absorbed by the 8-? resistor is 55.125 W. Source transformation involves converting a voltage source into a current source or vice versa. In this case, the 7A current source and the 2V voltage source can be transformed into a 14? resistor and a 14A current source in parallel. The resulting circuit is a series circuit with the 6? and 8? resistors in series, and the 14? and 2? resistors also in series. The total resistance in the circuit is 30?. Using Ohm's law, the total current in the circuit is V/R = 21/30 = 0.7 A. The voltage drop across the 8? resistor is I*R = 0.7*8 = 5.6 V. Therefore, the current through the 8? resistor is 5.6/8 = 0.7 A. To calculate the power absorbed by the 8? resistor, we use the formula P = I^2*R, where I is the current through the resistor and R is the resistance. Substituting the values, we get P = (0.7)^2*8 = 3.92 W. However, we have to remember that this is the power absorbed by the resistor, not the power delivered by the source. The power delivered by the source is V*I = 21*0.7 = 14.7 W. Since the circuit is purely resistive, the total power delivered by the source is equal to the total power absorbed by the resistors in the circuit. Therefore, the power absorbed by the 8? resistor is 14.7 - 11.78 = 2.92 W.