Look up the p K b of aneline in aqueous solution. Discuss what the value means in terms of the base strength of aniline in water. Will aneline appear to be a stronger or weaker base in acetic acid as a solvent compared to water as a solvent? Explain.

The pKb of aniline in aqueous solution is \approx imately 4.6. This means that aniline is a weak base in water. The lower the pKb value, the stronger the base is. Aniline is weaker than ammonia (pKb = 4.75) which is a common base. Aniline appears to be a stronger base in acetic acid as a solvent compared to water as a solvent because acetic acid is less basic than water. The weaker the solvent, the stronger the basicity of the solution. This is because the solvent can donate or accept protons from the solute. In the case of aniline, it can accept protons from acetic acid since acetic acid is a weaker acid than water. This results in an increase in the concentration of aniline ions in the solution, making it a stronger base.