Hydrochloric acid is usually obtained as a 36% hydrochloric acid solution. If it is 13.42 M, what is the density of this solution? What is its molality? Density = g/mL Molality = m No need to show work.

The density of the solution can be calculated using the formula: {eq}\text{ Density} = \frac{\text{ mass}}{\text{ volume}} {/eq} Since we know the concentration of hydrochloric acid (13.42 M) and the percentage of the solution (36%), we can assume that 1000 mL of the solution will have a mass of 1000 g (i.e., a density of 1 g/mL). Therefore, we can calculate the mass of hydrochloric acid present in 1000 mL of the solution as: {eq}\text{ Mass of HCl} = \text{ Volume}times\text{ Concentration}times\text{ % purity} {/eq} Substituting the values given in the problem, we get: {eq}\text{ Mass of HCl} = 1000 \text{ mL}times13.42 \text{ M}times0.36 = 4831.2 \text{ g} {/eq} Substituting the mass and volume values in the density formula, we get: {eq}\text{ Density} = \frac{4831.2 \text{ g}}{1000 \text{ mL}} = 4.8312 \text{ g/mL} {/eq} The molality of the solution is given by the formula: {eq}\text{ Molality} = \frac{\text{ moles of solute}}{\text{ mass of solvent (in kg)}} {/eq} Since the mass of solvent (i.e., water) is not given in the problem, we cannot directly calculate the molality of the solution.