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10.07.2022 - 11:56

How much concentrated 18 M sulfuric acid is needed to prepare 250 mL of a 6.0 M solution?

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How much concentrated 18 M sulfuric acid is needed to prepare 250 mL of a 6.0 M solution?

Answers (1)

Janell April 2, 2023 в 14:12

To solve this problem, we need to use the formula: C1V1 = C2V2 where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the concentration of the final solution, and V2 is the final volume of the solution. In this problem, we know that we need to prepare a 6.0 M solution with a final volume of 250 mL. The concentration of the stock solution is 18 M (given in the problem). So we can plug these values into the formula and solve for V1: 18 M x V1 = 6.0 M x 250 mL V1 = (6.0 M x 250 mL) / 18 M V1 = 83.3 mL Therefore, we need 83.3 mL of 18 M sulfuric acid to prepare 250 mL of a 6.0 M solution.

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