15.07.2022 - 01:19

How many mL of acetone are required to make an 8.42 % v/v aqueous solution in a 300 mL volumetric flask?

Question:

How many mL of acetone are required to make an 8.42 % v/v aqueous solution in a 300 mL volumetric flask?

Answers (1)
  • Lillian
    April 13, 2023 в 10:30
    To calculate the mL of acetone required, we need to use the following formula: C1V1 = C2V2 where C1 is the initial concentration of acetone, V1 is the initial volume of acetone, C2 is the final concentration of the solution, and V2 is the final volume of the solution. Here, C1 and V1 are unknown, C2 is 8.42% v/v (which means 8.42 mL of acetone per 100 mL of solution), and V2 is 300 mL. Plugging in the values, we get: C1V1 = (8.42/100)*300 Simplifying, we get: C1V1 = 25.26 Now, we can assume that the final volume of the solution is 300 mL, which means the volume of water required is 300 - V1. We can substitute this in the above equation, and get: C1V1 = (8.42/100)*300 C1V1 = 25.26 C1*(300-V1) = 300*0.0842 C1*(300-V1) = 25.26 C1V1 - C1*300 = -25.26 C1V1 - 300*(8.42/100)*V1 = -25.26 C1*(300-V1) - 25.26 = -25.26 C1*(300-V1) = 0 From the last equation, we can see that either C1 or V1 must be zero. However, since we know that we need some acetone in the solution, the only possible solution is that V1 is zero. This means we need to add 25.26 mL of acetone to 300 mL of water to get an 8.42% v/v aqueous solution in a 300 mL volumetric flask.
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