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10.07.2022 - 07:31

How is the equation of a line that is parallel to y= -4x +2, and passes through the point (-4,9) found?

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How is the equation of a line that is parallel to y= -4x +2, and passes through the point (-4,9) found?

Answers (1)

Alline April 15, 2023 в 09:12

The equation of a line that is parallel to the given line will have the same slope as the given line, but a different y-intercept. The slope of the given line is -4, so the slope of the parallel line will also be -4. Using point-slope form, we can start with y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We are given the point (-4,9), so we can substitute those values in: y - 9 = -4(x - (-4)) Simplifying, we get: y - 9 = -4(x + 4) y - 9 = -4x - 16 Finally, we can rearrange this equation into slope-intercept form (y = mx + b) by adding 9 to both sides: y = -4x - 7 Therefore, the equation of the line that is parallel to y = -4x + 2 and passes through the point (-4,9) is y = -4x - 7.

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