Gold ore typically contains 10 grams of gold per 1000 kilograms of ore, and the current value of gold is $1185 per ounce. What mass of ore in tons (1 ton = 2000 pounds) must be refined to obtain $1 million worth of gold?
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Gold ore typically contains 10 grams of gold per 1000 kilograms of ore, and the current value of gold is $1185 per ounce. What mass of ore in tons (1 ton = 2000 pounds) must be refined to obtain $1 million worth of gold?
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Margie April 19, 2023 в 03:31To solve this problem, we need to convert the current value of gold from dollars per ounce to dollars per gram. $1185 per ounce / 31.1 grams per ounce = $38.09 per gram Next, we need to determine how much gold is in 1000 kilograms of ore: 10 grams of gold / 1000 kilograms of ore = 0.01 grams of gold per kilogram of ore Now we can calculate how much ore is needed to obtain $1 million worth of gold: $1,000,000 worth of gold / $38.09 per gram of gold = 26,245 grams of gold 26,245 grams of gold / 0.01 grams of gold per kilogram of ore = 2,624,500 kilograms of ore Finally, we need to convert kilograms of ore to tons: 2,624,500 kilograms of ore / 1000 kilograms per ton = 2,624.5 tons of ore Therefore, 2,624.5 tons (1 ton = 2000 pounds) of ore must be refined to obtain $1 million worth of gold.
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