21.07.2022 - 10:28

Find the roots, x_1 and x_2, of x2 – 5x -14 = 0.


Find the roots, {eq}x_1 {/eq} and {eq}x_2 {/eq}, of {eq}x^2 – 5x -14 = 0{/eq}.

Answers (1)
  • June
    April 18, 2023 в 14:11
    To find the roots of a \quadratic equation {eq}ax^2 + bx + c = 0{/eq}, we can use the \quadratic formula: {eq}x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} {/eq} In this case, we have {eq}a = 1{/eq}, {eq}b = -5{/eq}, and {eq}c = -14{/eq}. Substituting these values into the formula, we get: {eq}x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(1)(-14)}}{2(1)} {/eq} Simplifying: {eq}x = \frac{5 \pm \sqrt{25 + 56}}{2} {/eq} {eq}x = \frac{5 \pm \sqrt{81}}{2} {/eq} {eq}x = \frac{5 pm 9}{2} {/eq} So, the roots are {eq}x_1 = -2{/eq} and {eq}x_2 = 7{/eq}. We can check that these are indeed the roots by substituting them back into the original equation and verifying that it holds true.
Do you know the answer?

Leave a comment

Not sure about the answer?
Find the right answer to the question Find the roots, x_1 and x_2, of x2 – 5x -14 = 0. by subject Equations, and if there is no answer or no one has given the right answer, then use the search and try to find the answer among similar questions.
Search for other answers
New questions in the category: Equations

Password generation