Find the magnitude and direction in the 2.0 ohm resistor in the circuit (Let R = 2.5 ohm and V = 1.5 V.)
Question:
Find the magnitude and direction in the {eq}2.0 Omega {/eq} resistor in the circuit (Let {eq}R = 2.5 Omega and V = 1.5 V. {/eq})
circuit
Answers (1)
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Answers (1)
LenaApril 11, 2023 в 06:56
To find the magnitude of the current flowing through the circuit, we first need to find the equivalent resistance of the circuit.
The resistors {eq}R_1 {/eq} and {eq}R_2 {/eq} are in parallel, so their equivalent resistance is given by:
{eq}frac{1}{R_{equiv}}=frac{1}{R_1}+frac{1}{R_2}\ \frac{1}{R_{equiv}}=frac{1}{2.5 Omega}+frac{1}{4.0 Omega}\ \frac{1}{R_{equiv}}=0.4 \text{ S}^{-1}\ R_{equiv}=frac{1}{0.4 \text{ S}^{-1}}=2.5 Omega {/eq}
Now we can find the magnitude of the current by using Ohm's Law:
{eq}V=IR\ I=frac{V}{R}\ I=frac{1.5 \text{ V}}{2.5 Omega}\ I=0.6 \text{ A}{/eq}
So the magnitude of the current flowing through the {eq}2.0 Omega {/eq} resistor is {eq}0.6 \text{ A}. {/eq}
To find the direction of the current, we can use the right-hand rule for conventional current flow. If we curl our fingers in the direction of the magnetic field, which is out of the page, and our thumb points in the direction of the current, then our thumb points to the right. Therefore, the direction of the current flowing through the {eq}2.0 Omega {/eq} resistor is to the right.
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