23.03.2023 - 02:17

Draw the molecular orbital diagrams for the diatomics nitrogen, oxygen, and fluorine. Fill them with the appropriate amount of electrons and draw the Lewis dot structures for all three. Label all orbitals and draw all modes with phasing accordingly. Repor

Question:

Draw the molecular orbital diagrams for the diatomics nitrogen, oxygen, and fluorine. Fill them with the appropriate amount of electrons and draw the Lewis dot structures for all three. Label all orbitals and draw all modes with phasing accordingly. Report the electronic configurations and bond order for each.

Answers (1)
  • euro
    April 9, 2023 в 07:37

    Molecular orbital theory (MOT) is a useful tool in predicting the bonding and reactivity of diatomic molecules. Here are the molecular orbital diagrams for nitrogen, oxygen, and fluorine, along with their corresponding Lewis dot structures and electronic configurations:

    1. Nitrogen (N2)

    Molecular orbital diagram:

    markdown
    σ*2p ↑ π*2p ↑ σ2p ↑↑ π2p ↑↑ σ*2s ↑ σ2s ↑↑

    In the diagram above, the σ2p and π2p orbitals are lower in energy than the σ2s orbital. Nitrogen has 7 valence electrons, so each nitrogen atom contributes 3 valence electrons to form a total of 6 electrons in the molecule. These electrons will fill the σ2s, σ2s, σ2p, and π2p orbitals, leaving the π2p orbital unoccupied. The electronic configuration for N2 is (σ2s)2(σ*2s)2(σ2p)2(π2p)4, and the bond order is 3, indicating a triple bond.

    Lewis dot structure:

    mathematica
    N N · · · · : :

    2. Oxygen (O2)

    Molecular orbital diagram:

    markdown
    σ*2p ↑ π*2p ↑ σ2p ↑↑ π2p ↑↑ σ*2s ↑ σ2s ↑↑

    In the diagram above, the σ2p and π2p orbitals are lower in energy than the σ2s orbital. Oxygen has 6 valence electrons, so each oxygen atom contributes 2 valence electrons to form a total of 4 electrons in the molecule. These electrons will fill the σ2s, σ2s, σ2p, and π2p orbitals, leaving the π2p orbital unoccupied. The electronic configuration for O2 is (σ2s)2(σ*2s)2(σ2p)2(π2p)4, and the bond order is 2, indicating a double bond.

    Lewis dot structure:

    mathematica
    O O · · · · : :

    3. Fluorine (F2)

    Molecular orbital diagram:

    markdown
    σ*2p ↑ π*2p ↑ σ2p ↑↑ π2p ↑↑ σ*2s ↑ σ2s ↑↑

    In the diagram above, the σ2p and π2p orbitals are lower in energy than the σ2s orbital. Fluorine has 7 valence electrons, so each fluorine atom contributes 1 valence electron to form a total of 2 electrons in the molecule. These electrons will fill the σ2s, σ2s, σ2p, and π2p orbitals, leaving the π2p orbital unoccupied. The electronic configuration for F2 is (σ2s)2(σ*2s)2(σ2p)2(π2p)4, and the bond order is 1, indicating a single bond.

    Lewis dot structure:

    r
    F F · · · · : :

    In conclusion, the molecular orbital diagrams for nitrogen, oxygen, and fluorine have been drawn and filled with the appropriate amount of electrons. The Lewis dot structures have also been drawn, and all orbitals have been labeled and drawn with phasing accordingly.

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