Determine the molarity of a 15.0% by mass Hydrogen Peroxide solution. The density of Hydrogen Peroxide is 1.054 g/mL. The 15.0% by mass can be broken apart into 15.0 g Hydrogen Peroxide and 100.0 g so

To determine the mass percent of water in the hydrate {eq}BaCl_2cdot2H_2O {/eq}, we need to first calculate the molar mass of the hydrate. Molar mass of {eq}BaCl_2{/eq} = 137.33 g/mol Molar mass of {eq}2H_2O{/eq} = 36.02 g/mol Therefore, molar mass of {eq}BaCl_2cdot2H_2O{/eq} = (137.33 g/mol) + 2(18.02 g/mol) = 203.37 g/mol Now, we need to find the mass of water in the hydrate. Mass of {eq}2H_2O{/eq} in {eq}BaCl_2cdot2H_2O{/eq} = 2 (18.02 g/mol) = 36.04 g/mol The mass percent of water in {eq}BaCl_2cdot2H_2O{/eq} can be calculated as: Mass percent of {eq}2H_2O{/eq} = (mass of {eq}2H_2O{/eq} / molar mass of {eq}BaCl_2cdot2H_2O{/eq}) x 100 = (36.04 g/mol / 203.37 g/mol) x 100 = 17.7 % Therefore, the mass percent of water in {eq}BaCl_2cdot2H_2O{/eq} is 17.7 %.