07.07.2022 - 20:42

Classify how the amortization of a patent is reported in the statement of cash flows. a. operating activity: add to net income b. operating activity: deduct from net income c. investing activity d. financing activity e. significant non-cash activity

Question:

Classify how the amortization of a patent is reported in the statement of cash flows.

a. operating activity: add to net income

b. operating activity: deduct from net income

c. investing activity

d. financing activity

e. significant non-cash activity

Answers (0)
  • Treva
    April 7, 2023 в 06:40
    A. {eq}NaNO_2{/eq} is a salt of a weak acid ({eq}HNO_2{/eq}) and a strong base ({eq}NaOH{/eq}). Therefore, it can act as a weak base. B. {eq}NaNO_2{/eq} is the conjugate base of a weak acid ({eq}HNO_2{/eq}). When dissolved in water, it reacts with water to form {eq}OH^-{/eq} ions in a hydrolysis reaction. The equilibrium constant for this reaction is given by {eq}K_b=frac{[OH^-][HNO_2]}{[NaNO_2]} {/eq}. Since {eq}NaNO_2{/eq} is a strong electrolyte, its concentration in solution is equal to its molarity, i.e., {eq}[NaNO_2]=2.00 M{/eq}. The concentration of {eq}HNO_2{/eq} can be calculated using its acid dissociation constant: {eq}K_a=frac{[H^+][NO_2^-]}{[HNO_2]}=4.5times10^{-4} {/eq}. Since the acid is weak, we can assume that most of it remains protonated (i.e., in the form of {eq}HNO_2{/eq}) in solution. Therefore, we can use the \approx imation that {eq}[HNO_2]approx0{/eq}. Solving for {eq}[OH^-]{/eq}, we get: {eq}[OH^-]=sqrt{frac{K_b[NaNO_2]}{[HNO_2]}}=sqrt{frac{K_w}{K_a}[NaNO_2]}=sqrt{frac{1times10^{-14}}{4.5times10^{-4}}times2.00} M=5.33times10^{-3} M{/eq} Using the definition of pH, we can calculate the pH of the solution: {eq}pH=-log_{10}[H^+]=-(-log_{10}[OH^-])=log_{10}[OH^-] = -log_{10}(5.33times10^{-3})=2.27{/eq} Therefore, the correct answer is not listed among the given choices. The closest answer is option (a), which has a pH of 1.52.
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