An oxygen tank has a pressure of 12 atm at 295 K. The maximum pressure that the tank can hold is 25 atm. What is the maximum temperature at which the tank can be stored? (a) 610 K (b) 590 K (c) 350 K (d) 140 K (e) 0.98 K.

The pressure of a gas at a constant volume is directly proportional to its temperature (Charles's law). Therefore, we can use the following proportionality: {eq}frac{P_1}{T_1} = \frac{P_2}{T_2} {/eq} where {eq}P_1{/eq} and {eq}T_1{/eq} are the initial pressure and temperature, {eq}P_2{/eq} is the maximum pressure the tank can hold, and {eq}T_2{/eq} is the maximum temperature at which the tank can be stored. Substituting the given values, we get: {eq}frac{12 atm}{295 K} = \frac{25 atm}{T_2} {/eq} Solving for {eq}T_2{/eq}, we get: {eq}T_2 = \frac{25 atm times 295 K}{12 atm} = 614.58 K {/eq} Since the question asks for the maximum temperature that the tank can be stored at, the answer is (a) {eq}610 K{/eq}.