a) What percent by mass of each element is in adenosinetriphosphate? (C_{10}H_{16}N_5P_3O_{13} MW = 507,182 dfrac{g}{mol}) 1 – Carbon 2 – Hydrogen 3 – Nitrogen 4 – Phosphorus 5 – Oxygen b) If 0.147 g of ATP was added to 60 mL water, what woul

a) To calculate the percent by mass of each element in adenosinetriphosphate, we need to find the molar mass of each element, add them up, and then divide the mass of each element by the total molar mass, multiplying by 100 to get the percentage. Molar mass of Carbon = 12.011 g/mol Molar mass of Hydrogen = 1.008 g/mol Molar mass of Nitrogen = 14.007 g/mol Molar mass of Phosphorus = 30.974 g/mol Molar mass of Oxygen = 15.999 g/mol Total molar mass of adenosinetriphosphate = (10 ? 12.011) + (16 ? 1.008) + (5 ? 14.007) + (3 ? 30.974) + (13 ? 15.999) = 507.182 g/mol Percentage of each element by mass: Carbon = (10 ? 12.011 ? 507.182) ? 100 = 28.22% Hydrogen = (16 ? 1.008 ? 507.182) ? 100 = 1.60% Nitrogen = (5 ? 14.007 ? 507.182) ? 100 = 6.09% Phosphorus = (3 ? 30.974 ? 507.182) ? 100 = 5.85% Oxygen = (13 ? 15.999 ? 507.182) ? 100 = 58.24% b) To calculate the concentration of ATP in water, we need to use the formula: concentration = mass ? (volume ? Molar mass) Mass of ATP = 0.147 g Volume of water = 60 mL = 0.06 L Molar mass of ATP = 507.182 g/mol Concentration of ATP = 0.147 ? (0.06 ? 507.182) = 0.00485 M Therefore, the concentration of ATP in water would be 0.00485 M.