A waterbed filled with water has the dimensions 8.5 ft by 7.5 ft by 9.5 inches. Taking the density of water to be 1.00 g/cubic centimeter, determine the number of pounds of water required to fill the water bed.

To find the number of pounds of water required to fill the waterbed, we first need to convert the dimensions from feet to inches, since density is given in grams per cubic centimeter: 8.5 ft = 102 inches 7.5 ft = 90 inches 9.5 inches = 9.5 inches Next, we need to find the volume of the waterbed by multiplying these dimensions together: Volume = 102 in x 90 in x 9.5 in Volume = 87,030 cubic inches Now we can convert this volume to cubic centimeters by multiplying by the conversion factor 1 cubic inch = 16.39 cubic centimeters: Volume = 87,030 in3 x (16.39 cm3 / 1 in3) Volume = 1,426,330 cm3 Finally, we can find the mass of the water required to fill the waterbed by multiplying the volume by the density of water: Mass = 1,426,330 cm3 x 1.00 g/cm3 Mass = 1,426,330 g To convert the mass from grams to pounds, we can divide by the conversion factor 453.59 grams per pound: Mass = 1,426,330 g / 453.59 g/lb Mass = 3,141.6 lb Therefore, it would take \approx imately 3,141.6 pounds of water to fill the waterbed.