01.08.2022 - 09:34

# A. The data below was collected on a trip driving from El Paso to San Antonia on a bus 560 miles traveling at avg speed of 60 miles per hr, create a graph with the time(x-axis) and distance(y-axis). B. Estimate distance the bus travels in i. 2 hrs, ii.

Question:

A. The data below was collected on a trip driving from El Paso to San Antonia on a bus 560 miles traveling at avg speed of 60 miles per hr, create a graph with the time(x-axis) and distance(y-axis).

B. Estimate distance the bus travels in i. 2 hrs, ii. 2 3/4 hrs, iii. 3.5 hrs, iv. 7.25 hrs.

C. Describe in words a rule you can use to calculate the distance traveled for any given time for this trip.

 Time(Hrs) Dist.(Mi). 1 60. 2 120. 3 180. 4 240. 5 300 6 360. 7 420. 8 480. 9 540. 10 600.
• April 2, 2023 в 14:46
B. i. The bus would travel 120 miles in 2 hours. ii. The bus would travel \approx imately 165 miles (60 miles for the first hour, and 60 x 0.75 miles for the additional 45 minutes) in 2 3/4 hours. iii. The bus would travel 210 miles in 3.5 hours. iv. The bus would travel 435 miles in 7.25 hours. To estimate the distance traveled, we simply need to find the corresponding point on the graph for the given time and read off the distance traveled. For example, at 2 hours, the graph shows that the bus has traveled 120 miles. C. The rule to calculate the distance traveled for any given time for this trip is: distance = time x 60. This is because the average speed of the bus is 60 miles per hour, so for every hour traveled, the distance covered would be 60 miles. Therefore, for any given time, we can simply calculate the distance by multiplying the time in hours by 60.
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Find the right answer to the question A. The data below was collected on a trip driving from El Paso to San Antonia on a bus 560 miles traveling at avg speed of 60 miles per hr, create a graph with the time(x-axis) and distance(y-axis). B. Estimate distance the bus travels in i. 2 hrs, ii. by subject Physics, and if there is no answer or no one has given the right answer, then use the search and try to find the answer among similar questions.
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