Electrical engineering

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10.07.2022 - 10:17

A rubber ball filled with air has a diameter of 25.0 cm and a mass of 0.540 kg. What force is required to hold the ball in equilibrium immediately below the surface of the water in a swimming pool?

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A rubber ball filled with air has a diameter of 25.0 cm and a mass of 0.540 kg. What force is required to hold the ball in equilibrium immediately below the surface of the water in a swimming pool?

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Chloe April 16, 2023 в 16:12

The force required to hold the ball in equilibrium immediately below the surface of the water in a swimming pool can be found by calculating the buoyant force acting on the ball. The buoyant force is equal to the weight of the fluid displaced by the ball. Since the ball is fully submerged, the displaced fluid is equal to the volume of the ball. Using the formula for the volume of a sphere, V = (4/3)?r?, with a diameter of 25.0 cm, the radius is 12.5 cm or 0.125 m. The volume of the ball is therefore V = (4/3)?(0.125 m)? = 0.00818 m?. The density of water is 1000 kg/m?, so the weight of the displaced water is W = mg = (0.00818 m?)(1000 kg/m?)(9.81 m/s?) = 80.1 N. Therefore, the required force to hold the ball in equilibrium immediately below the surface of the water in a swimming pool is 80.1 N.

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