A quarterback throws a football with an angle of elevation of 40^circ and a speed of 60 ft/s. Find the horizontal and vertical components of the velocity vector.
Question:
A quarterback throws a football with an angle of elevation of {eq}40^circ {/eq} and a speed of {eq}60 rm ft/s {/eq}. Find the horizontal and vertical components of the velocity vector.
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CharlotteApril 2, 2023 в 16:56
The horizontal and vertical components of the velocity vector can be found using the following formulas:
Horizontal component = speed x cos(angle of elevation)
Vertical component = speed x sin(angle of elevation)
Substituting the given values, we get:
Horizontal component = 60 ft/s x cos(40°) = 46.06 ft/s (rounded to two decimal places)
Vertical component = 60 ft/s x sin(40°) = 38.50 ft/s (rounded to two decimal places)
Therefore, the horizontal component of the velocity vector is 46.06 ft/s and the vertical component is 38.50 ft/s.
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