A person wants to launch a water balloon and hit the top of a tower, 50.0 meters away. The water balloon launcher is angled at 25 degrees. The water balloon leaves the launcher at 68 m/s. If the ballo

The height of the tower can be found using the kinematic equation: y = y0 + v0y*t - 1/2*g*t^2 where: y = height of the tower y0 = initial height (assume the water balloon launcher is at ground level) v0y = vertical component of initial velocity (v0y = v0*sin(theta)) g = acceleration due to gravity = 9.8 m/s^2 t = time it takes for the water balloon to hit the tower First, we need to find v0y: v0y = v0*sin(theta) v0y = (68 m/s)*sin(25 degrees) v0y = 29.05 m/s Next, we can find the time it takes for the water balloon to travel 50.0 meters horizontally: x = v0x*t 50.0 m = (68 m/s)*cos(25 degrees)*t t = 1.67 seconds Now that we have t, we can find the height of the tower: y = y0 + v0y*t - 1/2*g*t^2 y = 0 + (29.05 m/s)*(1.67 s) - 1/2*(9.8 m/s^2)*(1.67 s)^2 y = 49.2 meters Therefore, the height of the tower is \approx imately 49.2 meters.