A pack of M&M candies contains 20 red, 10 blue and 10 yellow candies. Two candies were randomly taken from the pack without replacement (taken candy was not returned to the pack). Find the probability that : a) both candies are red; b) the first candy i

a) The probability of drawing a red candy on the first draw is 20/40 (since there are 20 red candies in a pack of 40), and the probability of drawing a red candy on the second draw, without replacement, is 19/39. So the probability of drawing two red candies in a row is: (20/40) x (19/39) = 190/1560 = 19/156 Therefore, the probability of both candies being red is 19/156. b) The probability of drawing a yellow candy on the first draw is 10/40, and the probability of drawing a blue candy on the second draw, given that the first candy was yellow and not replaced, is 10/39 (since there are now 39 candies left in the pack and 10 of them are blue). So the probability of drawing a yellow candy followed by a blue candy is: (10/40) x (10/39) = 100/1560 = 5/78 Therefore, the probability of the first candy being yellow and the second candy being blue is 5/78.