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04.07.2022 - 01:41

A fast-food chain randomly attaches coupons for prizes to the packages used to serve french fries. Most of the coupons say “Play again,” but a few are winners. Of the coupons, 78 percent pay nothing, with the rest evenly divided between “Win a free order

Question:

A fast-food chain randomly attaches coupons for prizes to the packages used to serve french fries. Most of the coupons say ‘Play again,’ but a few are winners. Of the coupons, 78 percent pay nothing, with the rest evenly divided between ‘Win a free order of fries’ and ‘Win a free sundae.’

If each member of a family of three orders fries with her or his meal, what is the probability that someone in the family is a winner? (Round to three decimal places as needed.)

Answers (0)

Josephine April 4, 2023 в 06:51

We can solve this problem using the complement rule. The probability that no one in the family wins is the same as the probability that all three get "Play again" coupons. Since each coupon is independent, we can multiply the probabilities of each event: Probability of "Play again": 0.78 Probability of three "Play again" coupons: 0.78^3 = 0.474552 Probability of at least one winner: 1 - 0.474552 = 0.525448 Therefore, the probability that someone in the family is a winner is \approx imately 0.525.

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