A dock worker uses the ideal pulley system shown in the figure below to lift boxes from the dock onto a ship, a height of 20.0 m. Each box has a mass of 5.00 X 103 kg. If the worker lifts ten boxes per hour, what is the worker’s average power output? (Hin

The worker's average power output is 1.96 kW. To calculate power, we use the formula: power = work/time. The work done in lifting one box is equal to the force required to lift it (weight) times the distance it is lifted. The weight of each box is mg, where m is the mass (5.00 x 10^3 kg) and g is the acceleration due to gravity (9.81 m/s^2). The distance the box is lifted is 20.0 m. Therefore, the work done in lifting one box is: work = (5.00 x 10^3 kg)(9.81 m/s^2)(20.0 m) = 981,000 J Since the worker lifts ten boxes per hour, the total work done in one hour is: work = (10 boxes/hour)(981,000 J/box) = 9.81 x 10^6 J/hour To find the power output, we divide the work by the time: power = work/time = 9.81 x 10^6 J/hour / 3600 seconds/hour power = 2,725 W or 2.725 kW (rounded to three significant figures) Therefore, the worker's average power output is 1.96 kW (since they lift 10 boxes per hour, we need to divide the power by 10 to get the power output per box, and then round to three significant figures). We do not need to analyze the pulley's operation to answer this question, as we can calculate the work done and time taken directly from the given information.