A coffee manufacturer uses Colombian and Brazilian coffee beans to produce two blends, robust and mild. A pound of the robust blend requires 12 ounces of Colombian beans and 4 ounces of Brazilian beans A pound of the mild blend requires 6 ounces of Colomb

To solve this problem, we can use a system of equations. Let x and y be the number of pounds of the robust and mild blends produced, respectively. From the problem, we know that: - 12 ounces of Colombian beans are needed for each pound of robust blend. - 6 ounces of Colombian beans are needed for each pound of mild blend. - 4 ounces of Brazilian beans are needed for each pound of robust blend. - 10 ounces of Brazilian beans are needed for each pound of mild blend. - There are 60 bags of Colombian beans, equivalent to 60 x 85 = 5100 ounces. - There are 41 bags of Brazilian beans, equivalent to 41 x 85 = 3485 ounces. Using this information, we can set up the following system of equations: 12x + 6y = 5100 (equation representing Colombian beans) 4x + 10y = 3485 (equation representing Brazilian beans) Solving this system of equations, we get: x = 285 (approximately) y = 390 (approximately) Therefore, the coffee manufacturer should produce \approx imately 285 pounds of the robust blend and 390 pounds of the mild blend to use all the available Colombian and Brazilian beans.