A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 9 A, and that of the vacuum cleaner is 5.5 A. (a) Determine the power consumed by the blow-dryer. _____W (b) Determine the power consumed by

(a) The power consumed by the blow-dryer can be calculated using the formula P = VI, where P is power, V is voltage, and I is current. Therefore, P = 120 V x 9 A = 1080 W. (b) Similarly, the power consumed by the vacuum cleaner can be calculated as P = VI, where P is power, V is voltage, and I is current. Therefore, P = 120 V x 5.5 A = 660 W. (c) The energy used by the blow-dryer in 21 minutes can be calculated using the formula E = Pt, where E is energy, P is power, and t is time. Therefore, Ebd = 1080 W x 21 min x 60 s/min = 1,274,400 J. The energy used by the vacuum cleaner in one-half-hour can be calculated using the same formula. Therefore, Evc = 660 W x 30 min x 60 s/min = 1,188,000 J. The ratio of the energy used by the blow-dryer to the energy used by the vacuum cleaner can be calculated as Ebd/Evc = 1,274,400 J / 1,188,000 J = 1.07. Therefore, the blow-dryer uses 1.07 times more energy than the vacuum cleaner in the given time periods.