A 1500- W heater is designed to be plugged into a 120 V outlet. A. What current will flow through the heating coil when the heater is plugged in? Express your answer numerically in ampere using three significant figures. I = boxed{space} A B. What is th

A. The current flow, I can be calculated using Ohm's law which states that I = V/R, where V is the voltage and R is the resistance. Therefore, I = V/R = 120/((1500/120)) = 10 A (to 3 significant figures). B. The resistance of the heater can be calculated using Ohm's law again, since R = V/I. Therefore, R = V/I = 120/10 = 12 ? (to 3 significant figures). C. The amount of heat energy required to raise the temperature of the air in the living room can be calculated using the equation Q = mc?T, where Q is the heat energy, m is the mass of the air, c is the specific heat capacity of air, and ?T is the change in temperature. The mass of the air, m can be calculated using the density of air, ?, and the volume of the living room, V. Therefore, m = ?V = 1.20 x 3.00 x 5.00 x 8.00 = 144 kg. The heat energy required, Q is then given by Q = mc?T = 144 x 1006 x 10.0 = 1.453 x 10^7 J. The power of the heater, P can be calculated using P = VI = 120 x 10 = 1200 W. The time required, t can be calculated using the equation P = Q/t, since power is the rate of energy transfer. Therefore, t = Q/P = (1.453 x 10^7)/1200 = 12108.33 s. Converting this to minutes gives t = 201.81 minutes (to 3 significant figures).