A 100 N force is applied to the side of a crate resting on a level floor. The crate has a mass of 50 kg. If the coefficient of static friction is s = .25, is the 100 N force enough to make the crate

The 100 N force is not enough to make the crate accelerate. This is because the static frictional force that opposes the applied force is greater than 100 N, given by the equation Ff = sFn, where Ff is the frictional force, s is the coefficient of static friction, and Fn is the normal force (which is equal to the weight of the object on a level floor). In this case, Fn = (50 kg) x (9.8 m/s^2) = 490 N. Therefore, the maximum static frictional force is Ff = (0.25)(490 N) = 122.5 N. Since this is greater than the applied force of 100 N, the crate will not accelerate but will remain in static equilibrium.